The conversion of K₂Cr₂O₂ into Cr₂(SO₂)₂ is a process of a)Oxidation b)Reduction c)Decomposition c)Substitution
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Oxidation
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Answer:Given equationK2Cr2O7 → Cr2 (SO4)3It is an example of reduction process.Let us find the oxidation state of Cr in both K2Cr2O7 and Cr2 (SO4)3(1) K2Cr2O7 2(1) + 2(x) + 7(-2) = 02 + 2x – 14 = 02x – 12 = 02x = 12x = +6(2) Cr2 (SO4)32(x) + 3(-2) = 02x – 6 = 02x = 6x = +3Oxidation number of Cr changes from +6 in K2Cr2O7 to +3 in Cr2 (SO4)3. So, this is an example of reduction.
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