Question

The Coodinates are TriangleABC are A(-4,2) B(5,0), and C(4,4). Ca⁶lculate The Area Of ABC​

Answer 1

Step-by-step explanation:

Hope it helps u...:)

Thank you...

Answer 2

Answer:

$\large\boxed{\sf{17\:sq.\:units}}$

Step-by-step explanation:

Given there is a ∆ABC, whose coordinate of vertices are :-

• A = (-4,2)
• B = (5,0)
• C = (4,4)

We know that, area of a triangle having vertices, (x1,y1) ; (x2,y2) and (x3,y3) is given by the formula :-

• $\bold{\dfrac{1}{2}|x_{1}(y_{2}-y_{3})-x_{2}(y_{1}-y_{3})+x_{3}(y_{1}-y_{2})|}$

Now, substitute the values of coordinate of vertices according to this formula .

Therefore, we will get,

=> ar(∆ABC) = 1/2[|-4(0-4) -5(2-4)+ 4(2-0)|]

=> ar(∆ABC) = 1/2[|-4(-4) -5(-2) +4(2)|]

=> ar(∆ABC) = 1/2[| 16 +10 +8|]

=> ar(∆ABC) = (1/2) × (34)

=> ar(∆ABC) = 34/2

=> ar(∆ABC) = 17

Hence, the required area of ∆ABC is 17 sq. units