The Coordinates at the point which divides a line joining P(3, 5), Q(-7,-8) externally in the ratio 8:5 is
Answers
Answered by
2
Step-by-step explanation:
The coordinates of point when (x
1
,y
1
) and (x
2
,y
2
) are divided in m:n
(i) internally is ( m+nmx 2 +nx 1
m+n
my
2
+ny 1 )
(ii) externally (
m−n
mx
2 −nx 1
m−n
my
2
−ny
1 )
Let the point be P(h,k)
(1) For internal division
h=
2+3
2(4)+3(−1)
=
5
5
=1
k=
2+3
2(−5)+3(2)
=
5
−4
⇒P(1,
5
−4
)
(2) For external division
h=
2−3
2(4)−3(−1)
=
−1
8+3
=−11
k=
2−3
2(−5)−3(2)
=
−1
−10−6
=16
⇒P(−11,16)
Similar questions