The coordinates of 3 point are A(-1,-6), B(3,-12) and C(k,6). Find he value of k if AB is perpendicular to AC
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Answer:
- 17.
Step-by-step explanation:
If AB is perpendicular to AC, slope of AB must be equal to the negative reciprocal of the slope of AC.
We know,
Slope of a line is given by ( y₂ - y₁ ) / ( x₂ - x₁ ), where ( x₁ , y₁ ) and ( x₂ , y₂ ) are just two points lying the line.
Here,
⇒ Slope of AB = - 1 / slope of AC
⇒ { - 12 - ( - 6 ) } / { 3 - ( - 1 ) } = - 1 / [ ( - 6 - 6 ) / ( - 1 - k ) ]
⇒ ( - 12 + 6 ) / ( 3 + 1 ) = ( - 1 - k ) / ( - 12 )
⇒ - 6 / 4 = ( 1 + k ) / 12
⇒ - 3 / 2 x 12 = 1 + k
⇒ - 3 x 6 = 1 + k
⇒ - 18 = 1 + k
⇒ k = - 17
Hence the required value of k is - 17.
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