The coordinates of A and B are (3k, 8) and (k, -3) respectively. Given that the gradient of the line segment AB is 3, find the value of k.
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Answer:
Using the section formula, if a point (x,y) divides the
line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then (x,y)=(
m+n
mx
2
+nx
1
,
m+n
my2+ny
1
)
Substituting (x
1
,y
1
)=(1,2) and (x
2
,y
2
)=(2,3) and m=4,n=3 in the section formula, we get
R=(
4+3
4(2)+3(1)
,
4+3
4(3)+3(2)
)=(
7
11
,
7
18
)
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