The coordinates of A, B, C are (3, 4), (5, 2), (x, y) respectively. If area of ∆ABC = 3, show that x + y = 10
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A (3,4) ; B(5, 2); C(x, y)
ar. ABC = 3
1/2{3(2−y) + 5(y − 4) + x(4 − 2)} = 3
3(2−y)+5(y−4)+2x = 6
6 − 3y +5y − 20 + 2x = 6
2y + 2x = 20
x +y = 10
Hence proved!
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