The coordinates of a moving particle at any time 't' are given by x=at2 and y=bt3.The speed of the particle at time 't' is given by
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154
x=at(square) , y=bt(square)
so ,
Velocity in x direction, Vx=dx/dt=2at
Velocity in y direction. Vy=dy/dt=3bt(square)
so , net velocity , V = under root V(square)x+V(square)y
= under root 4at(square)+9b(square)t(2*square)
hope you will understand
so ,
Velocity in x direction, Vx=dx/dt=2at
Velocity in y direction. Vy=dy/dt=3bt(square)
so , net velocity , V = under root V(square)x+V(square)y
= under root 4at(square)+9b(square)t(2*square)
hope you will understand
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240
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