Question

the Coordinates of a moving particle at time t are x=9t,y=6+t square and z=t2/3.find the velocity and acceleration at t=3 sec

Answer 1

Answer:

velocity in x -axis direction v

x

=

dt

dx

=2ct

in y direction v

y

=

dt

dy

=2bt

therefore velocity is v=

v

x

2

+v

y

2

=2t

c

2

+b

2