Question

the Coordinates of a moving particle at time t are x=9t,y=6+t square and z=t2/3.find the velocity and acceleration at t=3 sec

Answer 1

Explanation:

Answer

velocity in x -axis direction

v

x

=

d t

d x

=

2ct

in y direction

v

y

=

d t

d y

=

2bt

therefore velocity is

v=

v

x

2

+v

y

2

=

2t

2

c 2

hope this helps u

Answer 2

Explanation:

the velocity in x - axis

v/x = dt/dx

2ct in y direction

v/y = dt/dy = 2bt

therefore the velocity is

vx2/+vy2 = 2t/2 = c2

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