Question

The coordinates of a point on X-axis which is
equidistant from the points A(2,-5) and B(-2,9)
will be:
(1) (-7,0) (ii) (0,7) (iii) (0, - 7) (iv) (7,0).
the​

Answer 1

Answer:

ans is (I) (-7,0)

Step-by-step explanation:

1. because according to distance formula point O. (X,0) is equidistant from OA and OB
2. so OA =OB
3. √ (2-X ) square +(-5-0) square = √(-2-x) square+ (9-0) square
4. squaring both sides we get 4+X*X -4x +25=4+X*X+ 4x+81
5. -8x= 81-25
6. -8x= 56
7. X= 56/-8
8. X = -7
9. so, the points are (-7,0)