Question

The coordinates of point A and B are (3,-5) and (1,-2) respectively. Then the ordinate of the point C on the line segment AB such that ACAB=47  is​

Answer 1

Given : point A and B are (3,-5) and (1,-2) respectively.  

point C on line such that AC : AB = 4 : 7

To Find : Coordinate of the point C on the line segment AB

Solution:

AC : AB = 4 : 7

BC = AB - AC

=> AC : BC  = 4  : 3

Hence point C divides line segment AB in 4 : 3 ratio

A(3,-5)  and B   (1,-2)

Point C divides in 4 : 3 ratio

=> C  = ( 4 * 1 + 3 * 3)/(4 + 3)  ,  ( 4 * (- 2)  +  3 * (-5) ) /(4 + 3)

=>  C = ( 13/7   ,  -23/7)

Coordinate of the point C  =  ( 13/7   ,  -23/7)

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Answer 2

Answer:

$53131 = \times { > 06 \leqslant y \div \leqslant \sqrt[ \times | \: \csc( \beta \% log_{ \gamma \sec( \gamma kz < - x - \sqrt[ < 3946 = 0696 \frac{ \leqslant \times 0 \div 11 \beta \pi \cos(\pi) }{?} ]{?} \times \frac{?}{?} ) }(?) ) | ]{?} \times \frac{?}{?} \times \frac{?}{?} }^{2} \times \frac{?}{?} \times \frac{?}{?} \times \frac{?}{?}$