the coordinates of point of intersection of the lines 3x+4y-18=0 and 4x-5y+7=0 are
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These two lines are represented by the equation a1x+ b1y+ c1= 0 and a2x + b2y + c2 = 0 respectively.
then
x1/ (b1c2−b2c1) = y1/(c1a2−c2a1) = 1/ (a1b2−a2b1)
then
x = (b1c2−b2c1) /(a1b2−a2b1);
y = (a2c1−a1c2)/(a1b2−a2b1)
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helina28:
ans is wrong
but how ??
the options given are a) (-2,-3) b (2,3) c (2,-3) d (-2,3)
2,3 is and put the value of x and Y in eqn
this question is of aakash module
Ye this question is aaksh module's
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