Question

The Coordinates of points on the x axis which are at a distance of 5 units from the point P(6-3)​

Answer 1

Answer:

Any point on X-axis has co-ordinates of form (x,0)

∴(x1,y1)=(6,−3) and (x2,y2)=(x,0) and d=5

∴d=(x2−x1)2+(y2−y1)2

5=(x−6)2+[0−(−3)]2=(x−6)2+32

Squaring on both sides 52((x−6)2+9)2

25=x2−12x+36+9

x2−12x+45−25=0⇒x2−12x+20=0⇒(x−10)(x−2)=0

∴x−10=0 or x−2=0⇒