Question

the coordinates of points P and Q are (4,3) and (2,-1) respectively. find the shortest distance between P and Q

Answer 1

Answer:

Displacement = 4.47 units.

Step-by-step explanation:

The displacement(shortest distance) between two points can be calculated by:

d = √((x1-x2)²+(y1-y2)²) . --(i)

Having,

'd' as displacement.

'x1,y1' as the co-ordinates of starting point.

'x2,y2' as the co-ordinates of the ending point.

Now, as we are given two points, let 'P1' and 'P2' be the two points respectively; thus,

P1(x1,y1) = (4,3).

P2(x2,y2) = (2,-1).

Now, for the shortest distance, simply put the points in the above mentioned formula (i):

d = √((4-2)² + (3-(-1))²)

d = √(2² + 4²)

d = √(4+16)

d = √(20)

d = 4.47 units