Question

the coordinates of the center of the circle if the ends of the diameters are (2,-5) and (-2,9)
WITH PROCESS
a) (0,0)
b) (2, -2)
c) (-5, 9)
d) (0, 2)

Answer 1

Answer:

As we know centre is the mid-point of diameter

so by section formula we can fine the coordinates of centre

Step-by-step explanation:

section formula for the point which is the midpoint is=

(x1+x2)/2=X and (y1+y2)/2=T

where (X, Y) is centre

.

this implimies..

X=(2-2)/2=0

Y=(-5+9)/2

=4/2=2

Hence,option d) is required coordinate I.e. (0,2)