The coordinates of the foci of the hyperbola - y2 -16x2 =16 are -
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Given :
y² - 16x² = 16 hyper bola
To Find : coordinates of the foci of the hyperbola
Solution:
y² - 16x² = 16
=> y²/16 - x²/1 = 1
=> y²/4² - x²/1² = 1
Vertical hyperbola
y²/a² - x²/b² = 1
a = 4
b = 1
c² = a² + b² = 16 + 1 = 17
c = √17
Foci = ( 0 , ±c)
( 0 , ±√17)
= ( 0 , √17) , ( 0 , - √17)
( 0 , ±√17) is the correct option
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