Question

the coordinates of the point equidistant from points (-1,8) and (3 4) are...​

Answer 1

Answer:

Answer :- C = ( 1,6 )

Step-by-step explanation:

Given :- A = (-1,8) , B = ( 3,4 )

To find :- coordinates of point equidistant from A and B .

Solution :-

Step 1) If the point is equidistant from A and B , then it must be mid point .

Step 2) Let , point C be the midpoint of A and B .

      We know mid point formula  , $( \frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

Step 3) substituting the points in the formula ,

we get

$= ( \frac{-1+3}{2} , \frac{8+4}{2}) \\ = (\frac{2}{2} , \frac{12}{2} )\\ = (1,6)$

Thus , (1,6) are the points equidistant from points A and B .

Answer :- C = ( 1,6 ) .

#SPJ3