The coordinates of the point on
axis which is equidistant from /(-3,4)
and (2,6) are
Answers
Answered by
2
Answer:
Let that point be ( a , 0 ), so, by using distance formula-
= > ( - 3 - a )^2 + ( 4 - 0 )^2 = ( 2 - a )^2 + ( 6 - 0 )^2
= > ( 3 + a )^2 + 4^2 = ( 2 - a )^2 + 6^2
= > ( 3 + a )^2 - ( 2 - a )^2 = 36 - 16
= > ( 3 + a - 2 + a )(3 + a + 2 - a ) = 20
= > ( 2a + 1 )( 5 ) = 20
= > 2a + 1 = 4
= > a = 3/2
Hence the point is ( 3/2 , 0 )
Similar questions