The coordinates of the point on x-axis which are equidistant from the points (-3,4) and (2,-5) are
A (20,0)
B (-23,0)
C (4/5,0)
D none of these
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AnswEr :-
(-3,4)____________________________(2,5)
Given two coordinates points (-3,4) & (2,5) we have to find the point on X - axis which is equidistant from the points.
Let the Point be (0,X)
by using distance formula:
=> √(x2 - x1)² + ( y2 - y1)²
Now point (0,X) is the equidistant from the points (-3,4) &(2,5)
√(-3 -X)² + (4 -0)² = √(2 - X)² + (3 - 0)²
(-3 -X )² +16 = (2 - X )² + 25
9 + x² + 6x + 16 = 4 + x² -4x + 25
10x = 4
x = 2/5
Hence the point in X - axis is (2/5 , 0)
Option D is correct
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