Math, asked by karankirat345, 1 year ago

The coordinates of the point on x-axis which are equidistant from the points (-3,4) and (2,-5) are
A (20,0)
B (-23,0)
C (4/5,0)
D none of these

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Answers

Answered by ShírIey
143

AnswEr :-

(-3,4)____________________________(2,5)

Given two coordinates points (-3,4) & (2,5) we have to find the point on X - axis which is equidistant from the points.

Let the Point be (0,X)

by using distance formula:

=> √(x2 - x1)² + ( y2 - y1)²

Now point (0,X) is the equidistant from the points (-3,4) &(2,5)

√(-3 -X)² + (4 -0)² = √(2 - X)² + (3 - 0)²

(-3 -X )² +16 = (2 - X )² + 25

9 + x² + 6x + 16 = 4 + x² -4x + 25

10x = 4

x = 2/5

Hence the point in X - axis is (2/5 , 0)

Option D is correct

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