Question

the coordinates of the point P are (-3,2).find the coordinates of the points Q which lies on the line joining P & origin such that OP=OQ

Answer 1

op=oq
o=-3
p=2
q=?
put the values of P and Q
-3×2=-3×Q
-6=-3×Q
make the subject be Q
Q=-6÷-3
Q=2