the coordinates of the point P are (-3,2).find the coordinates of the points Q which lies on the line joining P & origin such that OP=OQ
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op=oq
o=-3
p=2
q=?
put the values of P and Q
-3×2=-3×Q
-6=-3×Q
make the subject be Q
Q=-6÷-3
Q=2
o=-3
p=2
q=?
put the values of P and Q
-3×2=-3×Q
-6=-3×Q
make the subject be Q
Q=-6÷-3
Q=2
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