The coordinates of the point where the line 2(x-3)=y-8 meet the x-axis
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Answered by
6
take y=0, substitute it in given equation
2(x-3)=0-8
2(x-3) = -8
x-3 = -8/2
x-3 = -4
x= -4+3
x= -1
co ordinates =(-1 ,0)
2(x-3)=0-8
2(x-3) = -8
x-3 = -8/2
x-3 = -4
x= -4+3
x= -1
co ordinates =(-1 ,0)
Answered by
0
Answer:
take y=0, substitute it in given equation
2(x-3)=0-8
2(x-3) = -8
x-3 = -8/2
x-3 = -4
x= -4+3
x= -1
co ordinates =(-1 ,0)
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