. The coordinates of the point which is
equidistant from the three vertices of the
AAOB as shown in the figure is:
Y
(0, 2y) A
В
XE
>
Х
(2x, 0)
Y ү"
(a) (x, y)
(b) (y,x)
ху
(c)
(d)
y X
2'2
Answers
Answered by
1
Answer:
hope it will help full you
Step-by-step explanation:
Correct option is
A
(x,y)
Point which is equidistant from vertices of triangle is termed as circumcentre of that triangle. For a right triangle the circumcentre is the mid point of hypotenuse.
Thus here coordinates of circumcentre must be mid point of AB
(x,y)
Answer - Option A
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