The coordinates of the point which is equidistant from the vertices of the triangle formed by the points O(0, 0), A(a,0) and B(0, b), are :________.
Answers
The coordinates of the point which is equidistant from the vertices of the triangle formed by the points O(0, 0), A(a,0) and B(0, b), are :________.
Step-by-step explanation:
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Given: A triangle is formed whose vertices are O(0,0) , A(a,0) and B(0,b)
To find: Point that is equidistant from the vertices
Explanation: A centroid is a point which is equidistant from the vertices of the triangle. Let C denote the centroid. To calculate the centroid of the triangle, the formula used is:
C(sum of x coordinates of vertices/3, sum of y coordinate of vertices/3)
where x coordinates are 0,a and 0 respectively while y coordinates are 0,0,b respectively
= (0+a+0/3, 0+0+b/3)
=(a/3, b/3)
Therefore, the point that is equidistant from the vertices of the traingle is (a/3, b/3).