Math, asked by rajneeshkarwal, 1 month ago

The coordinates of the point which is equidistant from the vertices of the triangle formed by the points O(0, 0), A(a,0) and B(0, b), are :________.​

Answers

Answered by bharat7asikar
5

The coordinates of the point which is equidistant from the vertices of the triangle formed by the points O(0, 0), A(a,0) and B(0, b), are :________.

Step-by-step explanation:

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  2. I don't no
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Answered by GulabLachman
5

Given: A triangle is formed whose vertices are O(0,0) , A(a,0) and B(0,b)

To find: Point that is equidistant from the vertices

Explanation: A centroid is a point which is equidistant from the vertices of the triangle. Let C denote the centroid. To calculate the centroid of the triangle, the formula used is:

C(sum of x coordinates of vertices/3, sum of y coordinate of vertices/3)

where x coordinates are 0,a and 0 respectively while y coordinates are 0,0,b respectively

= (0+a+0/3, 0+0+b/3)

=(a/3, b/3)

Therefore, the point that is equidistant from the vertices of the traingle is (a/3, b/3).

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