the coordinates of the points of intersection of lin ax+by=9 and bx+ay=5 is (3,-1).find the value of a and b.
Answers
Answer:
given equations are :
ax + by = 7..........(1)
bx + ay = 5 .........(2)
according to question, (3,1) is the point of intersection of given equations.
so, (3,1) will satisfy both of given equations.
put (3,1) in equation (1),
3a + b = 7 ........(3)
put (3,1) in equation (2),
3b + a = 5......... (4)
multiplying 3 with equation (3) and then subtracting equation (4),
3(3a + b) - (3b + a) = 3 × 7 - 5
9a + 3b - 3b - a = 21 - 5
8a = 16 => a = 2 , put it in equation (3)
b = 7 - 3a = 7 - 6 = 1
hence, a = 2 and b = 1
the coordinates of the points of intersection of lin ax+by=9 and bx+ay=5 is (3,-1).find the value of a and b.
ax + by = 9
bx + ay = 5
adding both
3,-1 is intersection point so it lies on both line and will satisfy both line equations
3a - b = 9 eq1
3b - a = 5 eq2
3*eq1 + eq2
9a - 3b + 3b -a = 3*9 + 5
8a = 27 + 5
8a = 32
a = 4
3b -4 =5
3b = 9
b = 3
a =4 & b = 3