Question

The coordinates of the points P and Q are respectively (4, -3) and (-1, 7). Find the abscissa of a point R on the line segment PQ such that PR by PQ = 3 by 5 ????? o(〃＾▽＾〃)o​

Answer 1

Answer:

HEY MATE,

HERE IS YOUR ANSWER.....

ABSCISSA OF THE POINT WOULD BE 17/8

Step-by-step explanation:

SINCE ABSCISSA IS THE X CORDINATE AND BY SECTION FORMULA,

X CORDINATE OF POINT R= 3×(-1)+5×(4)/3+5

THIS IMPLIES R= 17/8

HOPE IT HELPS......

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