Question

The coordinates of the vertex (turning point of the parabolic graph) of the parabola
f(x) = 2x2 + px + q are (-3, 1), then
The value of p is
(A) 12
(C) 19
(B) -12
(D) -19​

Answer 1

Answer:

The value of $p=12.$

Step-by-step explanation:

The given equation of parabola is $f(x)=2 x^{2}+p x+q$ the coordinate of vertex is $(-3,1)$.

To find value of $p$.

We know that standard form of parabola is $y=a x^{2}+b x+c$ the $x$ coordinate of the vertex is $\frac{-b}{2 a}$.

On comparing the given equation with the standard equation of parabola we have, $a=2, b=p$.

So, the $x$ coordinate is represented as:

$\begin{aligned}&\frac{-p}{2(2)}=-3 \\&p=12\end{aligned}$

Therefore, the value of $p$ is $12 .$

#SPJ2