Question

The coordinates of the vertices of A,B,and C of a parallelogram ABCD are (-10,6) , (0,-1) and

(2,-5) respectively . Find the coordinates of the 4th vertex D​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest answer pls

so here we go

Step-by-step explanation:

let the point of intersection of both diagonals ie ac and bd be point o

so as diagonals of parallelogram bisect each other ao=co and bo=do

thus o is midpoint of both diagonals

so let A=(x1,y1)=(-10,6)

C=(x2,y2)=(2,-5)

let O=(x,y)

so by midpoint formula we get

x=x1+x2/2 y=y1+y2/2

substitute given values in it

we get x=-4 y=1/2

so this coordinates of point O are -4 and 1/2

so similarly bo=do

thus let B=(x1,y1)=(0,-1)

D=(x2,y2)=(to be found)

O=(x,y)=(-4,1/2)

so use midpoint formula again

you get

x2=-8 y2=2

thus required fourth coordinates of parallelogram ABCD are -8 and 2