the coordinates of the vertices of A,B,C,D of a parallelogram ABCD are -10,6 0,1 and 2,-5 Find the coordinates of D
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SINCE diagonals of a parallelogram bisect each other
mid point ac= midpoint bd
-10+2/2=0+x/2
x=-8
6+(-5)/2=1+y/2
y=-11-1=-12
d is (-8,-12)
mid point ac= midpoint bd
-10+2/2=0+x/2
x=-8
6+(-5)/2=1+y/2
y=-11-1=-12
d is (-8,-12)
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