The coordinates of three vertices of square ABCD are (−212,112),(−212,−3),
A(-212,112),B(-212,-3), and (2,112)C(2,112).
When point D is placed on this square, what will the perimeter of the square be?
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Answer:
ABCD =500
Step-by-step explanation:
D=709 because it is a right angled triangle
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