Question

The coordinates of three vertices of trapezium, ABCD, are A (3,5), B (-5,4) and C (1,-5). AD is parallel to BC and angle ADC is 90 degree. Find the coordinates of D

Answer 1

Answer:

mid points of AC=BD so,

(1+3/2,5-5/2)=(-5+x/2,4+y/2)

4/2=-5+x/2=9 do the same for you and also so,y=-4 so the coordinates of D=(9,-4)