the coordinates of triangle abc is not possible A(1, 1) B(3, 2) C( 5, 3)
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Given,\: A(x_{1},y_{1}) = ( 1,1 ) , \\B(x_{2},y_{2}) = ( 3,2) , C(x_{3},y_{3}) = ( 5,3 )
/* We have to show that A,B and C are collinear points */
Area \: of \: \triangle ABC \\= \frac{1}{2}|x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})|
= \frac{1}{2}|1(2-3)+3(3-1)+5(1-2)|\\= \frac{1}{2}|-1+3\times 2 +5(-1)|\\= \frac{1}{2}| -1+6-5|\\= \frac{1}{2} \times 0 \\= 0
Area \: of \: \triangle ABC = 0
Therefore.,
A,B\:and \:C \:are \: collinear\:points
A,B \:and \: C \: are \: doesn't \:form \:a \\triangle .
Step-by-step explanation:
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