Question

The coordinates of two objects with masses m1= 1 g., and m2= 2 g. moving in the xy-plane are given by
1() = ^2 − 6 ; 1() = −3, 2() = − 8; 2() = −2
where 1, 2, 1 and 2 are in meters and in seconds.
Calculate the gravitational force due to these objects at the instant that the velocity of the first object perpendicular to its acceleration.

Answer 1

Explanation:

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Answer 2

p

i

=p

f

0=mv

i

^

+mv

j

^

+2m

v

v

=−

2

v

i

^

−

2

v

j

^

∣

v

∣=

2

v

KE=

2

1

mv

2

+

2

1

mv

2

+

2

1

2m(

2

v

)

2

=mv

2

+

2

mv

2

=

2

3

mv

2