Question

The coordinates of two point A and B are (-3,3) and (2,-7)respectively. P is a point on the line segment ABBA such that AP:PB=2:3.find the coordinate of p without using square paper

Answer 1

Using section formula
m=2,n=3
So formula is
X=mx2+nx1/m+n
Y=my2+ny1/m+n
So substituting values
We get X=2(2)+3(-3)/2+3=4-9/5=-1
Y=2(-7)+3(3)/2+3=-14+9/5=-1

Answer 2

we can find the coordinates of p by section formula i. e.,
$mx2 + nx1 \div m + n \\ this \: is \: for \: x \: coordinate \: \\ for \: y \: coordinate \: \\ my2 + ny1 \div m + n$
.•. x=2(2)+3(-3)/2+3
=4-9/5
=-5/5=-1
.•. x=-1

similarly,
y=2(-7)+3(3)/2+3
=-14+9/5
=-5/5
=-1
.•. y=-1