Question

the coordinates of two points P and Q are (2, –3) and (–6, 5), then the value of (abscissa of P) – (ordinate of Q) is....................... ​

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Secondary School Math 5 points

If the coordinates of two points are P (- 2,3) and q (-3, 5) then find (abscissa of P - abscissa Q

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ishwarsinghdhaliwal

ishwarsinghdhaliwal Genius

Abscissa of P= -2

Abscissa of Q = -3

Abscissa of P-Abscissa of Q = -2-(-3) = -2+3=1

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ishwarsinghdhaliwal

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wifilethbridge Ambitious

Answer:

1

Step-by-step explanation:

Given : Coordinates of P = (-2,3)

Coordinates of Q = (-3,5)

To Find : abscissa of P - abscissa Q

Solution:

In the coordinate (x,y)

x is abscissa

y is ordinate

Abscissa of P = -2

Abscissa of Q = -3

Abscissa of P -Abscissa Q = -2-(-3) = -2+3 =1

Hence the value of Abscissa of P - Abscissa Q is 1