the correct answer is option (a)
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Answer:AE
Solution:
We know that,
Centroid of a triangle is the point of intersection of the medians of a triangle and also centroid of a triangle divides each median in the ratio 2:1.
Then,
We get,
AE/OE=2/1 and
CF/OF=2/1
AE=2OE......1. and
CF=2OF..............2
We know diagonals of a parallelogram bisect each other.
Therefore,
AO=OC
AE+OE=CF+OF
By eq1 and eq2 we get,
2OE+OE=2OF+OF
3OE=3OF
OE=OF........................3
Similarly we can prove,
AE=CF.........................4
By eq1,eq2,eq3,eq4 we get,
AE=2OE=2OF=CF..................5
Now,
We have
OE+OF=OE+OE. (by eq3)
EF=2OE
EF=AE. (by eq 5)
Answer:AE
Solution:
We know that,
Centroid of a triangle is the point of intersection of the medians of a triangle and also centroid of a triangle divides each median in the ratio 2:1.
Then,
We get,
AE/OE=2/1 and
CF/OF=2/1
AE=2OE......1. and
CF=2OF..............2
We know diagonals of a parallelogram bisect each other.
Therefore,
AO=OC
AE+OE=CF+OF
By eq1 and eq2 we get,
2OE+OE=2OF+OF
3OE=3OF
OE=OF........................3
Similarly we can prove,
AE=CF.........................4
By eq1,eq2,eq3,eq4 we get,
AE=2OE=2OF=CF..................5
Now,
We have
OE+OF=OE+OE. (by eq3)
EF=2OE
EF=AE. (by eq 5)
Ramlayaksingh3:
thank you for your answer sister :)
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