Question

the correct answer will be mark as brainliest answer and please answer must be with explanation ​

Answer 1

Question :

Multiply the monomials :

• $\tt{ 3x , {-4x}^{2} , {7x}^{3}}$

• $\tt{ {a}^{3} , - {6a}^{2}b , {2b}^{3}}$

• $\tt{ {16x}^{6} , {-10xy}^{2} , \dfrac{3}{5}{x}^{2}{y}^{2}}$

• $\tt{{-2p}^{4} , -4{p}^{2}{q}^{2} , \dfrac{3}{8}p{q}^{2}}$

Answer :

Main idea to solve :

Multiply bases ; add the terms.

1)

$\longrightarrow{\tt{ (3 \times 4 \times 7 ){x}^{(1 +2+3)}}}$

$\implies{\tt{ -84{x}^{6}}}$

2)

$\longrightarrow{\tt{ (6 \times 2){a}^{(3 + 2)}{b}^{(1+3)}}}$

$\implies{\tt{ -12{a}^{5}{b}^{4}}}$

3)

$\longrightarrow{\tt{ (16 \times \cancel{-10} \times \dfrac{3}{\cancel{5}}){x}^{(6+1+2)}{y}^{(2+2)}}}$

$\implies{\tt{ -96 {x}^{9}{y}^{4}}}$

4)

$\longrightarrow{\tt{ (-2 \times \cancel{-4} \times \dfrac{3}{\cancel{8}}){p}^{(4+2+1)}{q}^{(2+2)}}}$

$\implies{\tt{ 3 {p}^{7}{q}^{4}}}$

Answer 2

Step-by-step explanation:

bhen yeh Kya chal rha h Yaar?

Parth ki I'd hacked ho gyi !

usne bio mei Likha h..

Kuch baat hui ho toh please mujhe bta dio....

☹️