Math, asked by Umachandru238, 10 months ago

The correct answer will be marked as brainliest!!! Come on

Attachments:

Acekiller: what if both are right then
Rukhayya1101: both are correct use ur convenient method..

Answers

Answered by achuaiswarya112
1

Answer:

Step-by-step explanation:

Attachments:
Answered by Rukhayya1101
1

Answer:

p(x)=x*2+[a+1]x+b=0

p[2]=2*2+[a+1]2+b=0

4+2a+2+b=0

6+2a+b=0--------------1

p[-3]=[-3]*2+[a+1][-3]+b=0

9-3a-3+b=0

6-3a+b=0-------------------2

from 1 aqnd 2

6+2a+b=6-3a+b

2a=-3a

5a=0

a=0------put the value in 1

6+2a+b=0

6+b=0

b=-6

mark as brainliest if helpul...


Umachandru238: It’s helpful but sry achuaiswarya had answered first
Rukhayya1101: no problem...glad that it was helpful..bye
Similar questions