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Acekiller:
what if both are right then
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Answer:
p(x)=x*2+[a+1]x+b=0
p[2]=2*2+[a+1]2+b=0
4+2a+2+b=0
6+2a+b=0--------------1
p[-3]=[-3]*2+[a+1][-3]+b=0
9-3a-3+b=0
6-3a+b=0-------------------2
from 1 aqnd 2
6+2a+b=6-3a+b
2a=-3a
5a=0
a=0------put the value in 1
6+2a+b=0
6+b=0
b=-6
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