Question

The correct equation for terminal velocity is

.2/9a²(p-sigma)g/n

.29a(p-sigma)gn

.2/9a(p+sigma)g/n

.29a²(p+sigma)gn​

Answer 1

$v = \frac{2r^{2}( \rho - \sigma)g }{9 \eta}$

Here, r is the radius of spherical body, $\rho$ is the density of spherical body, $\sigma$ is the density of fluid, $\eta$ is the coefficient of viscosity of fluid and g is the acceleration due to gravity.

Hope, this helps...