Question

The correct expression for the critical angle will be, if () is the refractive index of refracting medium w.R.T. Incident medium

Answer 1

Answer:

Critical Angle = ic = $sin^-1(1/4)$

Explanation:

Assume,

$x$ = $refractive \ index$

$x2$ = $Refractive \ index \ of \ incident\ medium$

$x1$ = $Refractive\ index\ of \ refracting\ medium$

Given,

$So,$$x2/x1 = sin ic/sin90$°

               = $sin ic$  --------- $( equation 1 )$

From Given$x1/x2 = x$and from $equation 1$

$Critical Angle$ $= ic = sin^-1(1/4)$

Note :-

Critical Angle - The angle of incidence to which the angle of refraction is equivalent to $90$°.

Refractive Index - It is the ratio that the live of bending of a light-weight ray once passing from one medium to a different. It can even be outlined because the magnitude relation of the speed of a light-weight ray in a veryn empty area to the speed of sunshine in a substance.

To know more about this topic check out the following links :

https://brainly.in/question/39439780?referrer=searchResults

https://brainly.in/question/2935938?source=quick-results&auto-scroll=true&q=refractive%20index

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