Question

The correct expression for the time period (t) of a particle of mass (m) performing simple harmonic motion, where k is a constant, is ______.

Answer 1

Answer:

purely kinetic

Explanation:

refer these images for crystal clear understanding.

purely kinetic. At the mean position, the velocity of the particle in simple harmonic motion is maximum and displacement is minimum, that is x=0. Therefore, Potential energy =1/2 K x square = 0 and Kinetic energy=1/2 K(a square-0 square)=1/2 Ka square. Thus, the total energy in simple harmonic motion is purely kinetic.