Question

The correct formula of hexamine platinum (IV) chloride is
(A)
[Pt(NH2)61C1
(B)
[Pt(NH3)]C12
-4.
(C)
[Pt(NH3)2013
(D)
[Pt(NH3)ICIO​

Answer 1

Answer:

(D)

[Pt(NH3)ICIO

is your right answer

Answer 2

Answer:

The correct answer is : [Pt(NH₃)₆]Cl₄

Explanation:

(None of the given option is correct.)

Hexamine platinum (IV) chloride is the chloride salt of the metal ammine complex [Pt(NH₃)₆]⁴⁺.  It says that there are six ammonia ligands (NH₃) connected to the platinum particle, and four chloride particles (Cl⁻) connected with the compound.

The central metal atom is platinum(Pt) and its oxidation number is 4⁺.

Ammine(NH₃) is a neutral ligand and its oxidation number is 0.

So the charge on the Hexamine platinum complex will be : 4⁺ + (0)*6 = 4⁺.

The charge of the complex is 4⁺, which is balanced by the four 1⁻ chloride  particles.

[Pt(NH₃)₆]⁴⁺ (Hexamine platinum complex) + Cl⁻ (Chloride ion) = [Pt(NH₃)₆]Cl₄.

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