Question

The correct geometry and hybridization for XeF₄ are (1) octahedral, sp³d²
(2) trigonal bipyramidal, sp³d
(3) planar triangle, sp³d³
(4) square planar, sp³d²

Answer 1

$\sf{square \: planar \: or \: s {p}^{3} {d}^{2} }$

EXPLANATIONS:-

The hybridization of XeF4 = number of lone pairs + number of sigma bonds around Xe atom =2+4=6. The steric number 6 implies that hybridization is sp3d2 and hence the geometry is octahedral.

Answer 2

Answer:

$xef4 = \\ 2 + 4 \\ = 6$