Question

The correct increasing order of the oxidation state of sulphur in the anions

Answer 1

Answer:

Oxidation state of S

2

O

4

2−

2(x)+4(−2)=−2

2x=8−2

2x=6

x=3

Oxidation state of SO

3

2−

x+3(−2)=−2

x=6−2

x=4

Oxidation state of S

2

O

6

2−

2(x)+6(−2)=−2

2x=12−2

2x=10

x=5

So the oxidation state of sulphur in the anions S

2

O

4

2−

, S

2

O

4

2−

and S

2

O

6

2−

follows the order.S

2

O

4

2−

<SO

3

2−

<S

2

O

6

2−

.