Question

The correct order for the size of I, I+, I– is *
2 points
(I) I > I– > I+
(II) I > I+ > I–
(III) I– > I > I+
(IV) I+ > I– > I​

Answer 1

Answer:

THE CORRECT OPTION IS (III)

Answer 2

Option (iii) is correct.

Usually, negative ion species are larger in size than atomic level and positive ion species.

• When an electron is added to neutral atom iodine ( I ), it becomes a negative ion ( I⁻).
• Due to more electrons available in Iodine-negative ion( I⁻), there will be more electron-electron repulsion than attraction from the nuclear charge.
• Due to this more electron's repulsive force, electrons tend to move away from nuclear charge thereby increasing their size than a neutral iodine atom (I).
• When an electron is removed from a neutral iodine atom ( I ), it becomes a positive ion ( I⁺).
• Due to lesser electrons available in iodine-positive ion ( I⁺), there will be more attraction from nuclear charge than electron-electron repulsion.
• Due to this more nuclear charge attraction, electrons tend to move closer to the nuclear charge thereby decreasing their size than a neutral atom (I).

Hence, I⁻ > I > I⁺ is the correct order for the size.

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