Chemistry, asked by sajid7634, 1 year ago

The correct order of bond angles (smallest first) in H2S, NH3, BF3 and SiH4 is.

Answers

Answered by Noreen1256
39

Nh3 (107) < h2s (109.5 ) = sih4 (109.5) < bf3 (120)


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Answered by SaurabhJacob
20

The answer of the following question is as follows-

Bond angle of H2S (Hydrogen sulfide) is 90 degrees.

Bond of angle of NH3 (Ammonia) is 107 degrees.

Bond angle of BF3 (Boron trifluoride) is 120 degrees.

Bond angle of SiH4 (Silicon hydride) is 109.5 degrees.

Now, the correct order of the bond angles of H2S, NH3, BF3 and SiH4 in increasing order (smallest first) are as follows-

1. Hydrogen sulphide (H2S)

2. Ammonia (NH3)

3. Silicon hydride (SiH4)

4. Boron trifluoride (BF3)

That is,

'H2S < NH3 < SiH4 < BF3'

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