The correct order of electronegativity of the elements N, O, F and P is
a.F > N > P > O
b.F > O > P > N
c.F > O > N > P
d.N > O > F > P
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Answer:
c
Explanation:
according to their atomic radius..in period 2- the sequence is N,O,F
in period 2, the electronegitivity order is F>O>N
Phosphorus in the last.. But between O and N, N has more ionizing power. that means it has less negativity power that O,
So I will go for option (c)
I'm not so sure,got to check you more answers, I think !
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