Question

The correct order of increasing energy of atomic
orbitals for H-atom is
4p > 45 > 3d > 3p > 3s
4p = 45 > 3d > 3p = 3s
4p > 3d > 4s > 3p > 3s
4s = 4p > 3s = 3p = 3d​

Answer 1

Answer:

Orbitals are arranged with increasing energy on the basis of (n + l) rule.

The higher the value of (n + l) for an orbital the higher is its energy. Similarly the lower the value of (n + l) for an orbital the lower is its energy.

If two orbitals possess same (n + l) value, the orbital with lower (n + l) value will have the lower energy.

Let us find the energies of different orbitals

3s orbital:

n =3 , l= 0

(n + l) = (3 + 0) = 3

3p orbital:

n =3 , l= 1

(n + l) = (3 + 1) = 4

4s orbital:

n =4 , l= 0

(n + l) = (4+ 0) = 4

Both 3p and 4s orbitals have same (n + l) value, but the n value of 3p orbital is lower than 4s orbital hence, it will have lower energy.

3d orbital:

n =3 , l= 2

(n + l) = (3+ 2) = 5

The order of increasing energies of orbitals is 3s<3p<4s<3d.

Option A is correct.

Explanation:

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