Question

the correct order of spin only magnetic moment the following is atomic no Mn=25,Co=27,Ni=28,Zn=30

Answer 1

Answer: The order of spin only magnetic moment is given by: Mn > Co > Ni > Zn.

Explanation: Formula used to calculate the spin-only magnetic moment is given by:

$\mu_{\text{(Spin only)}}=\sqrt{n(n+2)}$    ....(1)

where,

n = Number of unpaired electrons in ground state electronic configuration.

• For Manganese (Z = 25)

Electronic configuration: $[Ar]3d^54s^2$

There are 5 unpaired electrons from the diagram below.

Spin only magnetic moment will be, Putting n = 5 in equation 1, we get:

$\mu_{\text{(Spin only)}}=\sqrt{5(5+2)}=\sqrt{35}$

• For Cobalt (Z = 27)

Electronic configuration: $[Ar]3d^74s^2$

There are 3 unpaired electrons from the diagram below.

Spin only magnetic moment will be, Putting n = 3 in equation 1, we get:

$\mu_{\text{(Spin only)}}=\sqrt{3(3+2)}=\sqrt{15}$

• For Nickel (Z = 28)

Electronic configuration: $[Ar]3d^84s^2$

There are 2 unpaired electrons from the diagram below.

Spin only magnetic moment will be, Putting n = 2 in equation 1, we get:

$\mu_{\text{(Spin only)}}=\sqrt{2(2+2)}=\sqrt{8}$

• For Zinc (Z = 30)

Electronic configuration: $[Ar]3d^{10}4s^2$

There are 0 unpaired electrons from the diagram below.

Spin only magnetic moment will be, Putting n = 0 in equation 1, we get:

$\mu_{\text{(Spin only)}}=\sqrt{0(0+2)}=\sqrt{0}=0$

Hence, the increasing order of spin only magnetic moment will be: Mn > Co > Ni > Zn.