Question

The correct order of stretching frequencies for C=C, C=C and C-Cis :
(A) C-C>C=CC=C
(B) C = C>C= C>C-C
(C) C-C>C=CC= C
(D) C = C <C-C>C=C​​​

Answer 1

Correct option is B)

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. 

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.Hence C=C<C−O and C−C

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.Hence C=C<C−O and C−CDue to electronegativity difference between C and O

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.Hence C=C<C−O and C−CDue to electronegativity difference between C and OC−O<C−C

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.Hence C=C<C−O and C−CDue to electronegativity difference between C and OC−O<C−C∴ Correct order of increasing bond length is :

Correct option is B)The C−H bond is the shortest due to the small size of both atoms & large electronegativity difference. The double bonds are shorter than single bonds.Hence C=C<C−O and C−CDue to electronegativity difference between C and OC−O<C−C∴ Correct order of increasing bond length is :C−H<C=C<C−O<C−C