Question

The correct order of the magnetic moment is
[25 Mn, 24Cr. 2Fe]
(A) Fe3+ > Cr+3 = Mn
(B) Fe3+ > Cr3+ > Mn4+
(C) Cr3+ = Mn4+ > Fe3+
(D) Fe3+ > Mn+4 > Cr3+​

Answer 1

Answer:

Explanation:{B} Fe3+>Cr3+>Mn4+

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Answer 2

Given: Given species are Mn, Cr and Fe.

To find: We have to find the magnetic order.

Solution:

The number of electrons present in $Fe^{+3}$ is 23.

Thus its electronic configuration is-

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {3d}^{5}$

Thus it has 5 unpaired electrons and a magnetic moment is √5(5+1)

=√30

=5.47

The number of electrons present in $Cr^{+3}$ is 21.

Thus its electronic configuration is-

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {3d}^{3}$

Thus it has 3 unpaired electrons and a magnetic moment is √3(3+1)

=√12

=3.46

The number of electrons present in $Mn^{+4}$ is 21.

Thus its electronic configuration is-

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {3d}^{3}$

Thus it has 3 unpaired electrons and a magnetic moment is √3(3+1)

=√12

=3.46

Thus, the order of magnetic moment is-

$Fe^{+3}>Cr^{+3}=Mn^{+4}$.